A charge of -6.09 μC is traveling at a speed of 6.65 × 106 m/s in a region of space where there is a magnetic field. The angle between the velocity of the charge and the field is 53.4o. A force of magnitude 8.59 × 10-3 N acts on the charge. What is the magnitude of the magnetic field?
F = q x V x B x Sin 53.4^{o}
8.59 x 10^{-3} = 6.09 x 10^{-6} x 6.65 x 10^{6} x B x Sin 53.4^{o}
Solving, we get : B = 2.64 x 10^{-4} T Answer
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